Sport Local February 18, 2025

Feyenoord vs AC Milan: UEFA Champions League Showdown

Feyenoord faces AC Milan for a crucial UEFA Champions League playoff match at San Siro. Feyenoord needs just a draw to advance, while Milan must win by two or more goals.


Feyenoord vs AC Milan: UEFA Champions League Showdown

In an exciting UEFA Champions League 2025 showdown, Feyenoord meets AC Milan to determine the first team to qualify for the knockout stage of the European tournament. The Dutch team arrives at San Siro with an advantage, needing only a win by the smallest margin or a goalless draw to advance to the next round. Meanwhile, Milan needs to win by two goals or more to continue in the competition.

The match between Feyenoord and AC Milan takes place today, February 18, at San Siro, marking the start of two consecutive days of European football also featuring the clash between Real Madrid and Manchester City. Santiago Giménez may be involved with the Italian team in this crucial encounter.

The odds for this match are already in motion, with AC Milan as favorites in the betting houses. The odds are as follows: AC Milan win at -303, draw at +400, and Feyenoord win at +800. These numbers reflect bettors' confidence in the Italian team to advance in the Champions League 2025.

In the first match between Feyenoord and AC Milan, Santiago Giménez started for the Italian team, but it was Feyenoord who surprised with an early goal from Igor Paixao. Despite having players like Christian Pulisic in the forward line, Milan failed to score, and the match ended without further goals.

The lineups for the first match were as follows: AC Milan: Maignan, T.Hernández, Pavlović, Thlaw, Walker, Reijenders, Fofana, Joao Félix, Christian Pulisic, Rafael Leao, Santiago Giménez. Feyenoord: Wellenreuther, Read, Beelen, Hancko, Smal, Moder, Milambo, Timber, Hadd Mussa, Ueda, Paizão.

The excitement of UEFA Champions League 2025 returns with this decisive matchup between Feyenoord and AC Milan in search of a place in the tournament's round of 16.